Physics, asked by supergalaxy6954, 9 months ago

An Iron Bar Length 10 Cm And Radius 1Cm Is Placed In A Magnetic Field Of Intensity 1000 With Its Length Parallel To The Direction Of The Field. Determine The Magnetic Moment Produced In The Bar If Permeability Of It’S Material Is Henry/M

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Answered by Archita893
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Assignment and Solutions

1. The relation between μ and H for a specimen of iron is as follows-

μ = [0.4/H + 12 × 10–4] Henry / meter

The value of H which produces flux density of 1 Tesla will be-

(A) 250 A/m (B) 500 A/m (C) 750 A/m (D) 103 A/m

Solution:(B) B = μH

or B = [0.4 / H + 12 × 10–4] H

or 1 = 0.4 + 12×10–4 H

H = 500 A/m

2. The correct curve between X and 1/T for paramagnetic materials is-

Solution: (A) X ∝ 1/T

3. The SI unit of magnetic flux is-

(A) Weber (B) Maxwel (C) Tesla (D) Gauss

Solution: (A) Φ = BA = Weber m2/m2 = Weber

4. The intensity of magnetic field due to an isolated pole of strength mp at a point distant r from it will be-

(A) mp / r2 (B) mpr2 (C) r2 / mp (D) mp / r

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