Question

An iron block of mass 2 kg, fall from a height 10 m. After
colliding with the ground it loses 25 % energy to
surroundings. Then find the temperature rise of the
block (Take sp. heat of iron 470 J/kg°C)​

Answer 1

Answer:

2kg=1000gram

height=10metre

1m=100cm

10m=100×10=1000

Explanation:

1000×1000/100×10-2

=99898...

the answer is not this let's take out the 25%

25/100=25

to be continued....

Answer 2

answer is  

0.159

question is

An iron block of mass 2 kg, fall from a height 10 m. After

colliding with the ground it loses 25 % energy to

surroundings. Then find the temperature rise of the

block (Take sp. heat of iron 470 J/kg°C)​

step by step answer

PE=2g×10=20g

Heat loss is 25%

So, remaining heat is 15g

15g=mcΔT

⇒ΔT=0.159°c

HOPE IT HELP YOU