Question

an iron cylinder of radius 1.4cm and length 8cm is found to weigh 369.6 grams .calculate the density of iron

Answer 1

Volume of the cylinder = $\pi r^{2} h$
= 22/7 * 1.4 * 1.4 * 8 
= 49.28 $cm^{3}$
Now density = mass/volume = 369.6/49.28 = 7.5 $cm^{3}/g$

So, density of iron is 7.5 $cm^{3}/g$.

Hope it will help you...!

Answer 2

Answer:

Volume of the cylinder =  \pi  r^{2} h

= 22/7 * 1.4 * 1.4 * 8  

= 49.28  cm^{3}  

Now density = mass/volume = 369.6/49.28 = 7.5  cm^{3}/g

So, density of iron is 7.5  cm^{3}/g.

=7500 kg\m^3

Explanation: