Question

An iron cylindrical pipe length is 10 meters in diameter, with a radius of 55 centimeters and a thickness of iron is 2 centimeters. Find the iron cube used in the pipes here.​

Answer 1

Height of pipe = 20 cm

External diameter = 25 cm 

External radius = 25/2 = 12.5 cm

Internal diameter = 25 - (1 + 1)

= 23 cm

Internal radius = 23/2 = 11.5 cm

Let external radius be R and the internal radius be r.

Total surface area of the pipe = 2πh(R + r) + 2π(R² - r²)

⇒ 2*22/7*20(12.5 + 11.5) + 2*22/7*{(12.5)² - (11.5²)

⇒ (44*480)/7 + (44*24)/7

⇒ 21120/7 + 1056/7

⇒ 22176/7

= 3168 cm²

Total surface area of the pipe is 3168 square cm.

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