Question

An iron pillar has some part in the form of a right circular cylinder and remaining in the form of a right circular cone. The radius of the base of each of cone and cylinder is 8 cm. The cylinderical part is 240 cm high and the conical part in 36 cm high. Find the weight of the pillar if one cu. Cm of iron weighs 7.8 grams.

Answer 1

Answer:

Step-by-step explanation

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Answer 2

The weight of the pillar if one cu. Cm of iron weighs 7.8 grams. is  395366.322 g

Step-by-step explanation:

Height of cylinder = 240 cm

Radius of cylinder = 8 cm

Volume of cylinder = $\pi r^2 h$

Volume of cylinder = $\frac{22}{7} \times (8)^2 (240)$

Volume of cylinder = $48274.2857 cm^3$

Height of cone =36 cm

Radius of cone = 8 cm

Volume of cone = $\frac{1}{3} \pi r^2 h$

Volume of cone = $\frac{1}{3} \times \frac{22}{7} \times (8)^2 (36)$

Volume of cone = $2413.7142 cm^3$

Total volume of pillar = Volume of cone + Volume of cylinder

Total volume of pillar = 2413.7142 + 48274.2857 = 50687.99

1 cubic cm = 7.8 grams

So, 50687.9999 cubic cm = $50687.99\times 7.8 = 395366.322$

Hence  the weight of the pillar if one cu. Cm of iron weighs 7.8 grams. is  395366.322 g

#Learn More :

An iron pillar has some part in the form of a right circular cylinder and remaining in the form of a right circular cone.The radius of the basre of each cone and cylinder is 8cm.the cylinderical part is 240cm high and the conical part is 6 cm high.find the weigh of the pillar if one cu.cm of iron weighs 7.8 grams

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