Question

An iron pillar has some part in the form of right circular cylinder and remaining in the form of the right circular cone. the radius of the base of the cone and cylinder is 8cm. find the cost of the canvas of the tent at the rate of Rs. 45 per m^2​

Answer 1

Answer:

395.37 kg

Step-by-step explanation:

Volume of the pillar = Volume of the cylindrical part + Volume of conical part

Volume of a Cylinder of Radius "R" and height "h" = πr square h

Volume of a cone = 1/3 πr square h where r is the radius of the base of the cone and h is the height.

Hence, Volume of the pillar =(22/7 × 8 × 8 × 240)+( 1/3× 22/7 × 8 square ×36)= 50688 cm cube

If one cu cm wieighs 7.8 grams, then 50688cm cube weighs 50688 × 7.8 =395366.4 grams or 395.37kg

Answer 2

Answer

${\textsf{\textbf{\pink{\underline{Given:− }}}}}$

Radius = 8 cm

Height of cylinder = 240 cm

the conical part in 36 cm high.

${\textsf{\textbf{\purple{\underline{To find:- }}}}}$

Weight of the pillar if one cu. cm of iron weighs 7.8 grams.

${\textsf{\textbf{\orange{\underline{ Solution :- }}}}}$

${\textsf{\textbf{\blue{\underline{ We know that }}}}}$

Volume of cylinder = πr²h

Volume of cone = ⅓πr²h

Now,

Volume of cylinder = 3.14 × 8 × 8 × 240

=> 48320.4 cm^3

Now,

⅓ × 3.14 × 8 × 8 × 36

1 × 3.14 × 8 × 8 × 12

3.14 × 64 ×12

2411.52 cm^3

Now,

Weight of pillar = Volume of cylinder + volume of cone

W = 48320.4 + 2411.52

W = 50730

Now,

1kg = 1000gm

7.8/1000 × 50730

0.0078 × 50730

395.4 kg

${\textsf{\textbf{\pink{\underline{Weight of pillar is 395 kg}}}}}$

@${{\underline{\blue{theanuragkumar}}}}$_