Question

interchange of signs should give correct equation​

Answer 1

Answer:

+ and -

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

$\begin{array}{l}(6)\: \: \: 10+10 \div 10-10 \times 10=10 \\ \\ \text{ \( \rm (A)+a n d - \) \qquad \boxed{\bf(B) }\( \underline{ \pmb{ \bf +\operatorname{and} \times }} \) \qquad (C) \( \div \) and \( \times \) \qquad (D) \( + \) and \( \div \)} \end{array}$

Correct option is [B].

$\rule{300pt}{1pt}$

By making the interchanges given in ( A ), the equation as

$10-10 \div 10+10 \times 10=10$

or 109=10 which is false.

By making the interchanges given in (B), the equation as

$\pmb{ 10 \times 10 \div 10-10+10=10 }$

or 10=10 which is true.

By making the interchanges given in (C), the equation as

$10+10 \times 10-10 \div 10=10$

or 109=10 which is false.

By making the interchanges given in (D), the equation as

$10 \div 10+10-10 \times 10=10 .$

or -89=10 which is false.