An iron pipe 20 CM long has exterior diameter equal to 14 CM. If the thickness of the pipe is 1 cm,then find whole surface area of pipe.
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Height=20 cm
exterior diameter= 14cm
Therefore, exterior radius(R)=14/2=7.
Thickness of Pipe= 1cm.
Therefore Inner Radius (r)=R - Thickness
7-1=6
Assuming that top and bottom are open, Whole surface area of Pipe=
2πh(R+r) + 2π (R^2-r^2)
2 x 22/7 (7+6) + 2 x 22/7 (7^2-6^2)
=44/7 x 13 + 44/7 x 13
=81.71 x2
=163.428
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