An iron pipe 20 cm long has exterior diameter equal to 25 cm. If the thickness of the pipe is 1 cm,find the whole surface of the pipe.
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3
CSA OF BIGGEST CYLINDER - AREA OF SMALLER CYLINDER
INNER CYLINDER'S RADIUS IS 25-1=24.
INNER CYLINDER'S RADIUS IS 25-1=24.
MRXYZ:
I mean CSA of smallest cylinder
thnx....
Answered by
22
height of iron pipe = 28 cm
exterior diameter = 25 cm
so the radius is = 25 /2 = 12.5
Thickness of the diameter = 1 cm
so the inner radius = 12.5 - 1 = 11.5 cm
Total surface area of the pipe = Outer curved surface area + inner curved surface area + area of two bases
2πRh +2πrh + 2 π(R²- r²)
2 × 22/7 × 12.5 × 20 + 2 ×22/7 × 11.5 × 20 + 2 ×22/7 × ( 12.5²-11.5²)
1571.42 + 1445.71+150.85
3197.98 cm²
exterior diameter = 25 cm
so the radius is = 25 /2 = 12.5
Thickness of the diameter = 1 cm
so the inner radius = 12.5 - 1 = 11.5 cm
Total surface area of the pipe = Outer curved surface area + inner curved surface area + area of two bases
2πRh +2πrh + 2 π(R²- r²)
2 × 22/7 × 12.5 × 20 + 2 ×22/7 × 11.5 × 20 + 2 ×22/7 × ( 12.5²-11.5²)
1571.42 + 1445.71+150.85
3197.98 cm²
thnx.........
thanks !!
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