an iron rod 28 cm long is to be bent to make a rectangle. the area of that rectangle should be 45sq. cm
Answers
Answer:
Step-by-step explanation:
A 34 cm long wire is bent in to a rectangle. The length of its diagonal is 13 cm. What are the lengths of the sides of the rectangle?
Answer
Perimeter of the rectangle = Length of the wire 2(Length + Breadth) = 34
⇒ Length + Breadth = 17
Let the length of the rectangle be x cm.
⇒ Breadth of the rectangle = (17 - x) cm.
Using Pythagoras theorem,
x
2
+(17−x)
2
=13
2
x
2
+289−34x+x
2
=169
2x
2
−34x+120=0
x
2
−17x+60=0
Discriminant =b
2
−4ac=289−240=49
x=
2a
−b±
b
2
−4ac
=
2
17±
49
=
2
17±7
=12or5
When length, x = 12 cm, breadth, 17 - x = 5 cm
When length, x = 5 cm, breadth, 17 - x = 12 cm
Thus, the lengths of the sides of the rectangle are 12 cm and 5 cm.
soluhttps://haygot.s3.amazonaws.com/questions/663441_627614_ans_2f10c73a5d10498eaf474e597c0c5af9.jpgtion