Physics, asked by shakeelahmed6872, 9 months ago

An iron rod of length 2m and cross-sectional area of 50
mm² stretched by 0.5 mm, when a mass of 250 kg is hung
from its lower end. Young’s modulus of iron rod is
(a) 19.6´10²⁰ N/m² (b) 19.6´10¹⁸ N/m²
(c) 19.6´10¹⁰ N/m² (d) 19.6´10¹⁵ N/m²

Answers

Answered by ShreyaSharma1976
0

Your answer is

19.6 \times  {10}^{10} \frac{n}{ {m}^{2} }

Hope it helps

Answered by hoodapraveen49
0

Answer:

19.6 x 10 10 m/m is the answer

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