Question

An iron rod of length = 50 cm at temperature 12 celcius at what temperature will it become 50.12

Answer 1

L' = L + L@(T2-T1)

50.12 = 50 + 50×12×10^(-6)[T2-12]

REARRANGING:

6×10^(-4)[T2-12] = 0.12

T2 -12 = 200

T2 = 212

Answer 2

An iron rod of length = 50 cm at temperature 12 celcius at what temperature will it become 50.12