Question

for what value of k will the consecutive terms 2k+1, 3k+3 and 5k-1 form an AP
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Answer 1

Heya!!!

Answer to your question:

In AP ,common difference remains same.

➡b-a=c-b

3k+3-(2k+1)=5k-1-(3k+3)

3k+3-2k-1=5k-1-3k-3

k+2=2k-4

k=6

Hope it helps ^_^