an iron rod of length x m is heated at 20⁰ c . what temperature will it be heated so that the iron rod double its length
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Answer:
The linear thermal expansion is given by
l=l_0(1+\alpha \Delta T)l=l
0
(1+αΔT)
l=0.500(1+19\times 10^{-6}\times 30)=0.5003 \:\rm ml=0.500(1+19×10
−6
×30)=0.5003m
Explanation:
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