An iron sphere of 1kg is moving with a velocity of 20m/s on a cmented floor. it comes to rest after travelling a distance of 50m. Find the force of friction between the sphere and the floor.
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Answer:
Step-by-step explanation:
Given:
Initial velocity (u) = 20m/s
final velocity= 0m/s
Distance=50 m
from, third equation of motion:
v² - u² = 2as
0² - 20² = 2 x a x50
a=-400/2x50
a=-4m/s²
From Newton's second law, F=ma
F=1x-4
=-4N
Therefore, a frictional force of -4N ( negative sign indicates force acts in opposite direction.)
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