Question

An iron sphere of mass 10kg is dropped from a height of 80 cm, if g=10m/s.calculate the momentum transferred to the ground by the body.
plz answer this correctly. ​

Answer 1

M = 10 kgVelocity just before striking Earth = Vv2 = u? +2 ghv2 = 02 + 2 * 9.8m/sec2* 0.80 mV = 3.96 m/secMomentum before striking earth = 10 kg *3.96 m/sec = 39.6 kg m /secAfter collision, both the iron sphere and theearth have the same momentum. The totalmomentum is = 39.6 m/sec.momentum conservation:39.6 = Momentum of ground +momentum of iron sphere= (mass of ground + mass of ironsphere ) * velocity of both= mass of ground * velocity of ground as sphere is negligible as compared to mass of ground.Momentum transfered to ground = 39.6 kgm/sec

Explanation:

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