An iron sphere of mass 1kg id dropped from a height of 10m . if the acceleration of the sphere is 9.8m/second. Calculate the momentum transferred from the ground by the ball
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Answered by
216
Hi friend,
We know that
S=ut +1/2 at²
Since initial velocity is 0,
S= 1/2 at²
T² = 2S/a
T²= 2×10/9.8
T = 1.428 secs.
Velocity = acceleration × time
Velocity = 9.8 ×1.428
Velocity = 14 m/s.
Momentum (p) = mv
P=1×14
P=14 kg m/s.
Hope this helped you a little!!!
We know that
S=ut +1/2 at²
Since initial velocity is 0,
S= 1/2 at²
T² = 2S/a
T²= 2×10/9.8
T = 1.428 secs.
Velocity = acceleration × time
Velocity = 9.8 ×1.428
Velocity = 14 m/s.
Momentum (p) = mv
P=1×14
P=14 kg m/s.
Hope this helped you a little!!!
Answered by
8
Answer:
MOMENTUM = 14 KG METRE/SECOND
Explanation:
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