Question

An iron sphere of mass 1kg is dropped from beight of 10m. If the acceleration of sphere is 9.8m/s2. calculate the momentum transferred to the ground by all.

Answer 1

velocity of the ball just before hitting the ground =
$\sqrt{2gh}$
$\sqrt{2 \times 9.8 \times 10}$
$\sqrt{196}$
= 14m/s
momentum = mv
1×14
=14m^2/s