please tell please questions no 18
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Hey mate ✌️✌️❤️❤️⬇️⬇️
Let side of 2nd square = x cm
Therefore, side of the 1st square = (2x+3) cm
A.T.Q, ares(1st) - area(2nd) =144
=> (2x+3)² - x² = 144
=> 4x² +9 +12x - x² - 144 =0
=> 3x² +12x - 135 =0
=> 3x² +25x - 15x - 135 =0
=> (x-5)(x+9)=0
=> x = 5, - 9
=> x = 5cm
Since length can't be negative
Therefore putting the value of x in 2x+3
Side = 13 cm and 24 cm
Thanks❤️❤️✌️✌️ plz Mark as brainliest
Let side of 2nd square = x cm
Therefore, side of the 1st square = (2x+3) cm
A.T.Q, ares(1st) - area(2nd) =144
=> (2x+3)² - x² = 144
=> 4x² +9 +12x - x² - 144 =0
=> 3x² +12x - 135 =0
=> 3x² +25x - 15x - 135 =0
=> (x-5)(x+9)=0
=> x = 5, - 9
=> x = 5cm
Since length can't be negative
Therefore putting the value of x in 2x+3
Side = 13 cm and 24 cm
Thanks❤️❤️✌️✌️ plz Mark as brainliest
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