Question

An iron sphere of mass 500 g is dropped from a height of 10 m. The momentum transferred to the ground by the sphere will be

(1 Point)​

Answer 1

Answer:

v = u + a*t

Initial Velocity u

m/s

Final Velocity v

m/s

Time t

s

Acceleration a

m/s²

RESET VALUES

ANSWER

Here, initial velocity of sphere, u=0

Distance travelled, s=80cm=0.8m

Acceleration of sphere, a=10ms−2

Final velocity of sphere when it just reaches the ground can be calculated using

v2−u2=2as

∴v2−0=2×10×0.8=16

or v=16=4ms−1.

Momentum of the sphere just before it touches the ground =mv=10×4=40kgms−1