An iron spherical ball of volume 232848 cm cube is melted and converted into a cone of vertical angle 120 then find its height
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V= πr²h/3
r = htan60° = √3h
v = π(3h²)h/3 = πh³
given that the volume of material present in the cone = 232848 cm
v = πh³ = 232848
h = ³√(23248/π) ≈ 42.0 cm
HOPE , IT HELPS ... ✌
___________________________
V= πr²h/3
r = htan60° = √3h
v = π(3h²)h/3 = πh³
given that the volume of material present in the cone = 232848 cm
v = πh³ = 232848
h = ³√(23248/π) ≈ 42.0 cm
HOPE , IT HELPS ... ✌
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