Question

An irregular-shaped piece of a metal is placed
into a graduated cylinder containing 50 ml of
water. The new volume is 65 ml. Using a balance
scale, mass of the metal is found to be 158 gm.
The density of unknown metal is:
(a) 2.43 gm/cm³
(b) 0.0949 gm/cm³
(c) 3.16 gm/cm³
(d) 10.53 gm/cm³​

Answer 1

Displacement of water in the graduated cylinder

= 65ml - 50ml = 15ml

15ml water = 15cm³

Density of unknown metal,

= 158gm/15cm³

= 10.53 gm/cm³

Therefore option D is the correct answer

Answer 2

Answer:

Density = Mass/Volume

Here we have to find the density of unknown metal whose mass is given...

When we place the metal piece in water it's volume increases by 15ml...

50ml Water + Irregular Piece of metal = 65ml

Metals volume= 65ml - 50ml = 15ml....

Step-by-step explanation:

Now we have to convert 15ml into cm³....

Remember...

1L = 1000cm³

So, 1000ml = 1000cm³

→ 1ml = (1000/1000)cm³

• 1ml = 1cm³
• So, the volume of the metal will be 1cm³×15= 15cm³

Density = Mass/Volume

Density = Mass/VolumeMass=158gm

Density = Mass/VolumeMass=158gmVolume=15cm³

Density of metal = 158gm/15cm³

15 )158( 1.53

-15↓

08

-75

50

-45

5 Ans-1.533333333gm

__________________

So the answer will be 1.53gm/cm³

Important Formulas

Density- Mass/Volume

1ml- 1cm³