Question

(i) A metallic square frame has a perimeter equal to 308 cm. It is bent into the
shape of a circle. Find the area of the circle so formed.

Answer 1

Answer:

7546  cm²

Step-by-step explanation:

Let the radius of the circle be r.

Total length(perimeter) would remain same.

⇒ perimeter of square = perimeter of circle

⇒ 308 = 2πr

⇒ 308 = 2(22/7) r

⇒ 308 x 7/44 = r

⇒ 49 = r

     hence,

area of circle = πr² = (22/7) (49)²

                     = 7546

Area of the circle is 7546 cm²

Answer 2

Answer:

• 7546 cm²

Step-by-step explanation:

Given

• Perimeter of square = 308 cm
• It is bent into the shape of circle

To find

• Area of circle formed

Solution

If a metallic square frame is bent and converted into the shape of circle. Then perimeter of square will be equal to the perimeter of circle.

Perimeter of square = Perimeter of circle

• 308 = 2πr
• 308 = (2 × 22/7 × r)
• 308 = (44/7 × r)
• r = 308 × 7/44
• r = 49

Hence, the radius of the circle formed is 49 cm.

Now:

Area = πr²

• 22/7 × 49 × 49
• 22/7 × 2401
• 7546

Hence, the area of the circle so formed is 7546 cm².