Question

An isocelles has perimeter 45 cm and each of the equal sides are 12 cm.Find the area of the triangle ​

Answer 1

Perimeter of isosceles triangle=30cm Length of equal sides=12cm Let third side of triangle=xcm According to problem, x+12+12=30 x+24=30 x=30−24 x=6 ∴ Third side of triangle=6cm Using Heron's formula Area of triangle= s(s−a)(s−b)(s−c) sq. units where s= 2 a+b+c s= 2 30 =15 Area of triangle= 15(15−12)(15−12)(15−6) cm 2 = 15×3×3×9 cm 2 =3×3× 15 cm 2 =9 15 cm 2 ∴ Area of triangle=9 15 cm 2

Step-by-step explanation:

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