find the derivative of (√x-3x)(x+1/x) .... [the answer is 3/2√x-6x-1/2x√x]...I want the right solution with steps
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Answer:
f(x)= (√x - 3x) (x + 1/x)
Step-by-step explanation:
First derivative:
d/dx[f(x)] = f' x=
(1/2√x-3) (x+1/x) + (1- 1/x^2) (√x-3x)
Simplify/ Rewrite:
-(12√x-3) x^3 + x/2x^5/2
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