An isolated and charged spherical soap bubble has a radius ‘r' and the pressure inside is atmospheric. if ‘t' is the surface tension of soap solution, then charge on drop is:
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FRIEND.
ΦTHANKYOU YOU ASKING.
QUESTIONS FRIEND
[HERE YOUR ANSWER]
Inside the pressure must be (4T)/r greater than outside pressure in bubble. This excess pressure is
provided by charge on bubble.
Explain the solution..
Φ (4T)/r = sigma^2/(2 epsilon_0)`
Φ(4T)/r = Q^2/( 16 pi^2 r^4 xx 2 epsilon_0)
Φ[ sigma = Q/(4 pi r^2)]`
Q = 8 pi r sqrt
(2 r T epsilon_0)
THANYOU...
FRIEND.
ΦTHANKYOU YOU ASKING.
QUESTIONS FRIEND
[HERE YOUR ANSWER]
Inside the pressure must be (4T)/r greater than outside pressure in bubble. This excess pressure is
provided by charge on bubble.
Explain the solution..
Φ (4T)/r = sigma^2/(2 epsilon_0)`
Φ(4T)/r = Q^2/( 16 pi^2 r^4 xx 2 epsilon_0)
Φ[ sigma = Q/(4 pi r^2)]`
Q = 8 pi r sqrt
(2 r T epsilon_0)
THANYOU...
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