An isolated unit north Pole experience a Force of 2 into 10 power minus 7 when kept at a distance of 1m from a magnetic Pole in air. The pole strength of the pole is
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Answer:M2 = 2 x 10^19 T
Answer:M2 = 2 x 10^19 TExplanation:
Answer:M2 = 2 x 10^19 TExplanation:The formula for the magnetic force between two object is given below;
Answer:M2 = 2 x 10^19 TExplanation:The formula for the magnetic force between two object is given below;Force acting on each pole is F
Answer:M2 = 2 x 10^19 TExplanation:The formula for the magnetic force between two object is given below;Force acting on each pole is FF = (μ0 x m1 x m2) / (d2 x 4π )
Answer:M2 = 2 x 10^19 TExplanation:The formula for the magnetic force between two object is given below;Force acting on each pole is FF = (μ0 x m1 x m2) / (d2 x 4π )Given the problem statement, we can say that F is the force acting on each pole, m1 and m2 are the magnetic strengths and d is the distance between the two magnets, μ0 is the magnetic permeability of the medium
Answer:M2 = 2 x 10^19 TExplanation:The formula for the magnetic force between two object is given below;Force acting on each pole is FF = (μ0 x m1 x m2) / (d2 x 4π )Given the problem statement, we can say that F is the force acting on each pole, m1 and m2 are the magnetic strengths and d is the distance between the two magnets, μ0 is the magnetic permeability of the mediumNow we are given that;
Answer:M2 = 2 x 10^19 TExplanation:The formula for the magnetic force between two object is given below;Force acting on each pole is FF = (μ0 x m1 x m2) / (d2 x 4π )Given the problem statement, we can say that F is the force acting on each pole, m1 and m2 are the magnetic strengths and d is the distance between the two magnets, μ0 is the magnetic permeability of the mediumNow we are given that;F = 2 x 10−7N
Answer:M2 = 2 x 10^19 TExplanation:The formula for the magnetic force between two object is given below;Force acting on each pole is FF = (μ0 x m1 x m2) / (d2 x 4π )Given the problem statement, we can say that F is the force acting on each pole, m1 and m2 are the magnetic strengths and d is the distance between the two magnets, μ0 is the magnetic permeability of the mediumNow we are given that;F = 2 x 10−7Nμ0 = 4π x 10−7N
Answer:M2 = 2 x 10^19 TExplanation:The formula for the magnetic force between two object is given below;Force acting on each pole is FF = (μ0 x m1 x m2) / (d2 x 4π )Given the problem statement, we can say that F is the force acting on each pole, m1 and m2 are the magnetic strengths and d is the distance between the two magnets, μ0 is the magnetic permeability of the mediumNow we are given that;F = 2 x 10−7Nμ0 = 4π x 10−7Nm1 = 1
Answer:M2 = 2 x 10^19 TExplanation:The formula for the magnetic force between two object is given below;Force acting on each pole is FF = (μ0 x m1 x m2) / (d2 x 4π )Given the problem statement, we can say that F is the force acting on each pole, m1 and m2 are the magnetic strengths and d is the distance between the two magnets, μ0 is the magnetic permeability of the mediumNow we are given that;F = 2 x 10−7Nμ0 = 4π x 10−7Nm1 = 1d = 1
Answer:M2 = 2 x 10^19 TExplanation:The formula for the magnetic force between two object is given below;Force acting on each pole is FF = (μ0 x m1 x m2) / (d2 x 4π )Given the problem statement, we can say that F is the force acting on each pole, m1 and m2 are the magnetic strengths and d is the distance between the two magnets, μ0 is the magnetic permeability of the mediumNow we are given that;F = 2 x 10−7Nμ0 = 4π x 10−7Nm1 = 1d = 1Putting the values in the given formula we get;
Answer:M2 = 2 x 10^19 TExplanation:The formula for the magnetic force between two object is given below;Force acting on each pole is FF = (μ0 x m1 x m2) / (d2 x 4π )Given the problem statement, we can say that F is the force acting on each pole, m1 and m2 are the magnetic strengths and d is the distance between the two magnets, μ0 is the magnetic permeability of the mediumNow we are given that;F = 2 x 10−7Nμ0 = 4π x 10−7Nm1 = 1d = 1Putting the values in the given formula we get;M2 = 2 x 10^19 T
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