Math, asked by vedangjuikar9, 4 months ago

ten years age mother was 4 times as old as his son and after3 years ratio of theirages will be 15:7 find their present ages [use two variable]​


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Answers

Answered by tanmayfonia
0

Age of mother 10 years ago was 3 times the age of her son. After 10 years, mother’s age will be twice that of his son. Find the ratio of their present ages?

Let at present mother's age is x and son's age is y years.

10 years ago their's age were x-10 and y-10 respectively. But as per questions, x-10 = 3(y-10)

Or, x-3y = -20 ……….(i)

Again after 10 years , their's age will be x+10 and y+10 respectively. But as per questions.

x+10 = 2(y+10)

Or, x-2y = 10 ………(ii)

By solving, we get y = 30 and x = 70

Ratio of their present age =

Mother : Son = 70 : 30 = 7 : 3

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