Question

an isoscale triangle has a base 6cm long and one of the equal sides is 5 cm long. find the area of triangle.

Answer 1

Hey dear here is your answer!!!!!

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We have been given:-

Base of Triangle = 6cm

Equal sides of triangle = 5cm.

To solve this question:-

Draw a perpendicular from the common vertex of the equal sides to the base of the triangle.

This perpendicular will bisect the base into two equal halves as well as act as height of the triangle.

Hence, AD = DC

Therefore, AD = DC = 3cm

Let the triangle be ABC and the perpendicular meet base at D.

Apply Pythagoras Theorem:-

(AB)²= (AD)² + (BD)²

(5)² = (3)² + (BD)²

25 - 9 = BD²

BD² = 16

BD = $\sqrt{16}$

BD = 4cm.

So, the height of the triangle is 4cm.

To find the are of the triangle we use the formula:-

Area = $\frac{1}{2}$ x Base x Height

Area =  $\frac{1}{2}$ x 6 x 4

Area = 12 cm²

So, the area of the triangle is 12cm² !

❣️⭐ Hope it helps you dear...⭐⭐❣️❣️