An isosceles right angle triangle has area 8 cm 2 . then the length of hypotenuse is .
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Let the length of each sides of isosceles triangle be xcm
Area of triangle = 1/2 base x altitude
Area = 8cm² (given)
∴ , 8 = 1/2 x²
x² = 16 = 4
x = 4
length of base and height = 4
now, length of hypotenuse = √ (base)² + (altitude)²
length of hypotenuse = √ (4)² + (4)²
length of hypotenuse = √ 16 + 16
= √32 = 4√2 cm
Area of triangle = 1/2 base x altitude
Area = 8cm² (given)
∴ , 8 = 1/2 x²
x² = 16 = 4
x = 4
length of base and height = 4
now, length of hypotenuse = √ (base)² + (altitude)²
length of hypotenuse = √ (4)² + (4)²
length of hypotenuse = √ 16 + 16
= √32 = 4√2 cm
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6
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