an isosceles right angled triangle has area 200cm^2 what is the length of the hypotenus
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Let each equal side of the isosceles right angled triangle be x cm
Area of the triangle
=1/2*x^2
Therefore,
1/2*x^2=200 cm^2
x^2=400
x=20 cm
The hypotenuse of the triangle is terefore,
sqrt(20^2*2)
=20 sqrt2 cm
.
hope it helps you
Area of the triangle
=1/2*x^2
Therefore,
1/2*x^2=200 cm^2
x^2=400
x=20 cm
The hypotenuse of the triangle is terefore,
sqrt(20^2*2)
=20 sqrt2 cm
.
hope it helps you
harjot14:
my answer was right
Answered by
3
Let the length of equal sides be a
Area = 200
=> 1/2 * a^2 = 200
=> a^2 = 400
=> a = 20 cm
Base = 20 cm
Perpendicular = 20 cm
Hypotenuse = sqrt ( 20^2 +20^2)
= sqrt(400+400)
= sqrt ( 800)
= 20 root2
Area = 200
=> 1/2 * a^2 = 200
=> a^2 = 400
=> a = 20 cm
Base = 20 cm
Perpendicular = 20 cm
Hypotenuse = sqrt ( 20^2 +20^2)
= sqrt(400+400)
= sqrt ( 800)
= 20 root2
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