An isosceles right triangle has an area 8sq.cm. The length of its hypotenuse is.......
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An isosceles right triangle has area 8 cm2. The length
(a) Given, area of an isosceles right triangle = 8 cm2
Area of an isosceles triangle = 1/2 (Base x Height)
⇒ 8 = 1/2 (Base x Base)
[∴ base = height, as triangle is an isosceles triangle]
⇒ (Base)2 =16 ⇒ Base= 4 cm

In ΔABC, using Pythagoras theorem
AC2 = AB2 + BC2 = 42 + 42 = 16 + 16
⇒ AC2 = 32 ⇒ AC = √32 cm
[taking positive square root because length is always positive]
Hence, the length of its hypotenuse is √32 cm.
Hey..!
Let the two equal sides of the isosceles right angled triangle be x cm.
Area = 1/2 × base × height
8 = 1/2 x^2
8 × 2= x^2
16 = x^2
4 cm = x
Now by the Pythagoras theorum,,
H^2 = x^2 + x^2. (H=hypotenuse)
H^2 = 2x^2
H^2 = 2 × 16. (x=4cm)
H^2 = 32
•°• H = root 32 cm