An isosceles right triangle has area 8 cm square . Find the length of its iso hypotenuse.
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4×sq.root of 2
area=1/2×b×h
but in this case b and h are equal therefore
area=1/2×b×b
8=1/2×b×b
16=b×b
b=4
now by pythagoras
the hypotenuse will be 4× sq root of 2
area=1/2×b×h
but in this case b and h are equal therefore
area=1/2×b×b
8=1/2×b×b
16=b×b
b=4
now by pythagoras
the hypotenuse will be 4× sq root of 2
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