Math, asked by llMichFabulousll, 22 days ago

an isosceles right triangle has area 8 cm square the length of its hypotenuse is ​

Answers

Answered by crazybot007
3

 \sf \pink{ \huge{Answer}}

Given,

area of an isosceles right triangle = 8 cm2

Area of an isosceles triangle = 1/2 (Base x Height)

⇒ 8 = 1/2 (Base x Base)

[∴ base = height, as triangle is an isosceles triangle]

⇒ (Base)2 =16 ⇒ Base= 4 cm

In ΔABC, using Pythagoras theorem

AC2 = AB2 + BC2 = 42 + 42 = 16 + 16

⇒ AC2 = 32 ⇒ AC = √32 cm

[taking positive square root because length is always positive]

Hence, the length of its hypotenuse is √32 cm.

Answered by Anonymous
5

{\underline {\boxed {\bf {\pink {\bigstar~Answer}}}}} \ \:

  • Given , Area of an isosceles right triangle = 8 cm2
  • Area of an isosceles triangle =
  •  \frac{1}{2}
  •  ( Base x Height)
  • ⇒  8 =
  •  \frac{1}{2}
  •  ( Base x Base )
  • [ ∴ base = Height , as triangle is an isosceles triangle ]
  • ⇒ ( Base )2 = 16 ⇒  Base = 4cm
  • In ΔABC , using Pythagoras theorem
  • AC2 = AB2 + BC2 = 42 + 42 = 16 + 16
  • ⇒ AC2 = 32 ⇒ AC = √32 cm
  • [ Taking positive square root because length is always positive ]
  • Hence , the length of its hypotenuse is √32 cm ...

{\underline {\boxed {\bf { {\bigstar~ \: i \:  \: hope \: this \: answer \:  \: will \:  \: help \:  \: you}}}}}

Similar questions