an isosceles right triangle has area 8 cm square the length of its hypotenuse is
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Given,
area of an isosceles right triangle = 8 cm2
Area of an isosceles triangle = 1/2 (Base x Height)
⇒ 8 = 1/2 (Base x Base)
[∴ base = height, as triangle is an isosceles triangle]
⇒ (Base)2 =16 ⇒ Base= 4 cm
In ΔABC, using Pythagoras theorem
AC2 = AB2 + BC2 = 42 + 42 = 16 + 16
⇒ AC2 = 32 ⇒ AC = √32 cm
[taking positive square root because length is always positive]
Hence, the length of its hypotenuse is √32 cm.
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- Given , Area of an isosceles right triangle = 8 cm2
- Area of an isosceles triangle =
- ( Base x Height)
- ⇒ 8 =
- ( Base x Base )
- [ ∴ base = Height , as triangle is an isosceles triangle ]
- ⇒ ( Base )2 = 16 ⇒ Base = 4cm
- In ΔABC , using Pythagoras theorem
- AC2 = AB2 + BC2 = 42 + 42 = 16 + 16
- ⇒ AC2 = 32 ⇒ AC = √32 cm
- [ Taking positive square root because length is always positive ]
- Hence , the length of its hypotenuse is √32 cm ...
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