Math, asked by Rupalimalviya, 6 months ago

An isosceles triangle has a base of 6cm long and one of the equal sides is 5cm long. Find the area of the triangle
please give me a step by step answer ​

Answers

Answered by prigoyal654
0

Answer:

Using all three sidesA = ½[√(a2 − b2 ⁄4) × b]

putting value of a b c in this formula u will get your answer

hope it helps you

Answered by pritykumari39
5

Answer:

Area of the given isosceles triangle is 12 cm^2.

Step-by-step explanation:

By using Heron's formula :

s= (a+b+c) /2= (5+5+6)/2=16/2=8cm

Now,

area of ∆= √s(s-a)(s-b)(s-c)

= √8(8-5)(8-5)(8-6)

= √8×3×3×2

= √96

= 12cm^2

So, area of the given isosceles triangle is 12cm^2.

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