An isosceles triangle has a base of 6cm long and one of the equal sides is 5cm long. Find the area of the triangle
please give me a step by step answer
Answers
Answered by
0
Answer:
Using all three sidesA = ½[√(a2 − b2 ⁄4) × b]
putting value of a b c in this formula u will get your answer
hope it helps you
Answered by
5
Answer:
Area of the given isosceles triangle is 12 cm^2.
Step-by-step explanation:
By using Heron's formula :
s= (a+b+c) /2= (5+5+6)/2=16/2=8cm
Now,
area of ∆= √s(s-a)(s-b)(s-c)
= √8(8-5)(8-5)(8-6)
= √8×3×3×2
= √96
= 12cm^2
So, area of the given isosceles triangle is 12cm^2.
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