Math, asked by preeta93, 9 months ago



an isosceles triangle has perimeter 30 cm and each of the equal sides is 12 cm. Find
the area of the triangle.

Answers

Answered by Anonymous
12

Answer:

perimeter = 30 cm

perimeter of an isoceles triangle = 2a+b

2a+b =30

2(12)+b=30

24+b=30

b=6

area of isoceles triangle = b/4*root4a^2-b^2

6/4*root576-36

3/2*root540

Answered by BlessedMess
0

First,let the third side be x.

It is given that the length of the equal sides us 12 cm and it's perimeter is 30 cm.

So,

30=12+12+x

⇒ 30 = 24 + x

⇒24  + x = 30

⇒  x= 30 - 24

⇒ x = 6

So,the length of the third side is 6 cm.

Thus,the semi perimeter of the isosceles triangle (s) = 30/2 cm =15 cm

By using Heron's Formula,

Area of the triangle,

 =  \sqrt{s(s - a)(s - b)(s - c)}

 =  \sqrt{15(15 - 12)(15 - 12)(15 - 6)}  \:  {cm}^{2}

 =  \sqrt{15 \times 3 \times 3 \times 9}  \:  {cm}^{2}

 = 9 \sqrt{15}  \:  {cm}^{2}

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