Question

an isosceles triangle has perimeter 30 cm and each of the equal sides is 12 cm. find the area of the triangle. ​

Answer 1

First,let the third side be x.

It is given that the length of the equal sides us 12 cm and it's perimeter is 30 cm.

• So,

$30=12+12+x$

$⇒ 30 = 24 + x$

$⇒24 + x = 30$

$⇒ x= 30 - 24$

$⇒ x = 6$

So,the length of the third side is 6 cm.

Thus,the semi perimeter of the isosceles triangle (s) = 30/2 cm =15 cm

By using Heron's Formula,

Area of the triangle,

$= \sqrt{s(s - a)(s - b)(s - c)}$

$= \sqrt{15(15 - 12)(15 - 12)(15 - 6)} \: {cm}^{2}$

$= \sqrt{15 \times 3 \times 3 \times 9} \: {cm}^{2}$

$= 9 \sqrt{15} \: {cm}^{2}$

Answer 2

Answer:

Perimeter of isosceles triangle=30cm

Length of equal sides=12cm

Let third side of triangle=xcm

According to problem,

x+12+12=30

x+24=30

x=30−24

x=6

∴ Third side of triangle=6cm

Using Heron's formula

Area of triangle=s(s−a)(s−b)(s−c)

​ sq. units

where s=2a+b+c​

s=230​=15

Area of triangle=15(15−12)(15−12)(15−6)

​cm2

=15×3×3×9

​cm

=3×3×15

​cm2

=915

​cm2

∴ Area of triangle=915

​cm2.

hope you lie it please mark as brainliest.