Math, asked by as17ee01, 4 months ago

An isosceles triangle has perimeter 30cm and
each of the equal sides is l2cmo find the area
of the triangle​

Answers

Answered by 000021
0

Step-by-step explanation:

Perimeter of the isosceles triangle=30cm

Each of the equal side is. =12cm

Total length of both the equal side=12×2cm

=24cm

Length of the unequal side. =30-24cm

=6cm

Area of isosceles triangle. =24×2cm

=48cm

Answered by Anonymous
1

☆ Solution ☆

Given :-

An isosceles triangle has perimeter 30cm and each of the equal sides is 12 cm.

To Find :-

The area of the triangle.

Step-by-Step-Explaination :-

Let the third side be x

So,

12 + 12 + x = 30

24 + x = 30

x = 30 - 24

x = 6

Hence,

The length of the third side is 6 cm.

Now,

The semi perimeter of the isosceles triangle (s) = 30/2 cm = 15 cm

By using Heron's Formula,

As we know that :-

Area of triangle = √ s ( s - a ) ( s - b ) ( s- c )

Putting the respective value,

√ 15 ( 15 - 12 ) ( 15 - 12 ) ( 15 - 6 ) cm²

√ 15 × 3 × 3 × 9 cm²

9 √ 15 cm²

Hence Solved !

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