Question

An isosceles triangle has perimeter 40 cm and each of equal sides is16 cm. Find aea of triangle

Answer 1

Answer:

chilll and listen 40= 16+16+× now solve 32-40=8 now using heron formula or for area of triangle 1/2×base×height

heron formula = √s(s-a)(s-b)(s-c) now solve from this two methods

Answer 2

formula for isosceles triangle is

$(1 \div 4)b \sqrt{ 4{a}^{2} - {b}^{2} }$

putting a= 16

b=8 ( a+a+b=40)

area will be 61.96cm²