Math, asked by umamehra2005, 7 months ago

an isosceles Triangle has perimeter 50 cm and
each of equal sides are 15cm. Find the area
of the triangle.​

Answers

Answered by sekar4576
11

Answer:

a + b + c = 50 cm

a and b are equal in an isoceles triangle

so,

15 cm + 15 cm + X = 50 cm ( perimeter)

Let the unknown side's measure be X

30cm + X = 50 cm

X = 50 cm - 30cm

X = 20 cm

so c = 20 cm

____________________________________

Area of a triangle = 1/2 b h

Answered by Aryan0123
24

Hi ⭐♥️❣️❤️

15 cm+ 15cm + x = 50 cm

x = 20cm

 \therefore \: 3 \: sides \: are  :  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \: a = 15 \: cm \:   \:  \:  \:  \:  \:  \:  \:   \: b = 15cm \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:

c = 20cm

Using herons formula;

s =  \frac{a + b + c}{2}

 =  \frac{50}{2}

 = 25cm

area =   \sqrt{s(s - a)(s - b)(s - c)}

  =   \sqrt{25(25 - 15)(25 - 15)(25 - 20)}

 =  \sqrt{25 \times 10 \times 10 \times 5}

 =  \sqrt{12500}

 = 111.8 \: cm {}^{2}

So the area is 111.8 cm^2

Hope it helps you

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