Question

An isosceles triangle with sides 13cm,13cm and base of 10cm is inscribed in a circle with radius r.What is the value of 'r'?

Answer 1

a=13,b=13,c=10

s =(a+b+c)/2 = (13+13+10)/2=18

area of triangle=[18(18-13)(18-13)(18-10)]^1/2 = (18*5*5*8)^(1/2) =60 cm^2 

let R be the radius,then
R=(a*b*c)/(4*area of triangle)

R=(13*13*10)/(4*60)= 7.04cm
pls mark as brainliest