Math, asked by anychristian568, 10 months ago

an isosceles tringle has perimeter 30cm and each of the equal sides is 12 cm .find the area of the triangle.​

Answers

Answered by Saby123
3

Answer:

The base is 8 cm.

Using herons formula, S = 16.

Area = √ [ 16 • 4 • 4 • 8 ] = 64√2 cm sq.

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Answered by BlessedMess
20

First,let the third side be x.

It is given that the length of the equal sides is 12 cm and it's perimeter is 30 cm.

So,30=12+12+x

⇒ 30 = 24 + x

⇒24  + x = 30

⇒  x= 30 - 24

⇒ x = 6

So,the length of the third side is 6 cm.

Thus,the semi perimeter of the isosceles triangle (s) = 30/2 cm =15 cm

By using Heron's Formula,

Area of the triangle,

 =  \sqrt{s(s - a)(s - b)(s - c)}

 =  \sqrt{15(15 - 12)(15 - 12)(15 - 6)}  \:  {cm}^{2}

 =  \sqrt{15 \times 3 \times 3 \times 9}  \:  {cm}^{2}

 = 9 \sqrt{15}  \:  {cm}^{2}

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