Question

an isoscles Right angled triangle with an area 12 m sq. find its base

Answer 1

can u just say the formula???!

Answer 2

Let the Base and perpendicular be a m

Area = 1 /2 Base × Height

=> 1/2 × a × a = 12

=> a^2 = 24

$a \: = \sqrt{24} \\ \\ a = 2 \sqrt{6}$