Chemistry, asked by arpitanayak2897, 1 year ago

An isotope with z > 83, which lies close to the band of stability, will generally decay through

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Answered by edwin555
0

An isotope with atomic number 83, this is also denoted by the symbol Z, when it lies to the band of stability it will generally decay through nuclear fussion.

In radioactivity, nuclear fussion is the process through which smaller nuclei of atoms join to form heavier atom.

Isotope with atomic number 83 is lighter hence decays through nuclear fussion to form a heavy nucleus atom.

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