Question

find the value of 'a' if f(a)=9 where f(x)= x^2-a+x

Answer 1

Howdy !!

your answer is ---
we have
f(x) = x^2-a+x

given,f(a) =9

so a^2 -a +a = 9

=> a^2 =9

=> a =√9

=> a = 3


hope it help you

Answer 2

Answer:

Step-by-step explanation:

Concept:

Algebraic expressions called polynomials include coefficients and variables. Indeterminates are another name for variables. For polynomial expressions, we can do mathematical operations like addition, subtraction, multiplication, and positive integer exponents, but not division by variable. x2+x-12 is an illustration of a polynomial with a single variable. There are three terms in this example: x2, x, and -12.

Polynomial is formed composed of the phrases Nominal, which means "terms," and Poly, which means "many." When exponents, constants, and variables are combined using mathematical operations like addition, subtraction, multiplication, and division, the result is a polynomial (No division operation by a variable). The classification of the phrase as a monomial, binomial, or trinomial depends on how many terms are included in it.

Given:

$f(x) = x^2-a + x$

$f(a) =9$

Find:

the value of $a$

Solution:

$f(x) =x^2 -a +x$

$f(a)=9$

if $x =a$ then $f(x) =f(a)$

Substitute $x$ in the place of $a$

$f(a) = a^2 - a +a$

$9 = a^2+0$

$a^2 =9$

$a=\sqrt9$

$a=3$

Hence the value of a =3

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