an obejct is placed at a distance of 10 cm from a convex mirror of focal length 15cm. find the position and nature of image
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u= -10cm
f=15cm
v=?
using mirror formula
1/f=1/u+1/v
1/15=1/-10+1/v
1/v=1/15-1/-10
1/v= -10-15/-150
1/v= -25/-150
1/v=1/6
v=6cm
position of image at 6cm
m= -u/v
m= -(-10)/6
m=10/6=1.6 approximately
The Magnifaction is positive so the nature of the image is virtual and erect
f=15cm
v=?
using mirror formula
1/f=1/u+1/v
1/15=1/-10+1/v
1/v=1/15-1/-10
1/v= -10-15/-150
1/v= -25/-150
1/v=1/6
v=6cm
position of image at 6cm
m= -u/v
m= -(-10)/6
m=10/6=1.6 approximately
The Magnifaction is positive so the nature of the image is virtual and erect
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