Question

An obj is dropped from the height of 19.6m find the distance travaled by obj in last second of its journey

Answer 1

$\Huge\underline\blue{\rm Answer :}$

$\large\red{\boxed{\sf x=14.6m }}$

$\Huge\underline\blue{\rm Solution}$

$\large\underline\pink{\sf Given: }$

• Object is droped from rest therefore initial velocity (u) = 0

• Height (s) = 19.6 m

• Time (t) = 1 sec

$\large\underline\pink{\sf To\:Find: }$

• Distance travelled in last second , Let it be = x = ?

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We know ,

$\Large{♡}$$\Large{\boxed{\rm s=ut+\frac12 at^2}}$

Here we have to Find distance travelled in last second (X)

So ,

$\Large{♡}$$\large{\boxed{\rm s-x=ut+\frac12 at^2}}$

On Putting value :

$\implies{\sf 19.6-x=0×t+\frac12 ×10×1^2}$

$\large\implies{\sf 19.6-x=5}$

$\large\implies{\sf 19.6-5=x}$

$\large\implies{\sf x=14.6m}$

$\Huge\red{♡}$$\LARGE\red{\boxed{\sf x=14.6m }}$

Hence ,

Distance travelled in last second of journey is 14.6m