Question

An object 0.02m high is placed at a distance 0.05 m from a concave mirror whose radius of curvature is 0.20m.find the nature ,size and position of image ?​

Answer 1

O= + 0.02 m

u= -0.05 m

R=0.20 m

Hence, f=R/2

f= -0.10 m

1/f= 1/v + 1/u

1/-0.1 = 1/v + 1/-0.05

-10=1/v -100/5

-10=1/v -20

-10 + 20=1/v

1/v=10

v=1/10

v=0.1 m

m= -v/u =I/O

m= -0.1/ -0.05

m=2

2=I/0.02

I=0.04 m

Hence, the image 0.04 m in height and is virtual, upright and magnified, it is formed 0.1 m behind the mirror.