an object 1 cm in height is placed at 20cm from a concave mirror a real inverted image 2 centimetre in height is formed at 40 cm from the mirror draw ray diagram and calculate its focal length and magnification produced by the mirror
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Explanation:
=> Here, an object 1 cm in height is placed at 20cm from a concave mirror and a real inverted image is formed at 40 cm from the mirror.
Thus, distance of Object, u = -20 cm
distance of Image, v = -40 cm
height of object = 1 cm
focal length = ?
=> For focal length, According to mirror formula:
1/f = 1/u + 1/v
1/f = 1/-20 + 1/-40
1/f = -2-1/40
1/f = -3/40
f = -(40/3)
f = -13.33 cm
=> Magnification produced by the mirror:
m = -v/u = - (-40/-20)
= - 2
Thus, focal length and magnification produced by the mirror for an object is -13.33 cm and -2 respectively.
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i hope it's helpful to u and mark me as a branliest I didn't draw the ray diagram it's easy u put rule 6 of concave mirror in ray diagram
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