An object 10cm high is placed 30cm
from a diverging lens of focal length
60cm Determine the nature and size of the
image
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given h=10cm
u=-30cm
f=-60cm
to find
h2=?
v=?
nature =?
1/v-1/u=1/f
1/v=1/f+1/u
1/v=-1/60-1/30
1/v=-1-2/60
1/v=-1/20
v=-20cm
h2=(v×h¹)/u
h²=(-20×10)/-30
h2=20/3cm
nature = virtual & erect
u=-30cm
f=-60cm
to find
h2=?
v=?
nature =?
1/v-1/u=1/f
1/v=1/f+1/u
1/v=-1/60-1/30
1/v=-1-2/60
1/v=-1/20
v=-20cm
h2=(v×h¹)/u
h²=(-20×10)/-30
h2=20/3cm
nature = virtual & erect
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